Monday, October 03, 2005

Mind your P’s and Q’s (or K’s)                  This lesson explains the relationship between the P and K values and the location of a person’s birth.  Parents were supposed to settle on a grid unit having a number that matched the number of one of their names.  When children were born, if a P or K value was used in their name, its value was directly linked to the number of their parents’ unit.  That number was usually identified by an E or O value in the names of one or more of the children.  The P value designated which column of 19 units included the number of the child’s birth.  The K value told the North-South displacement of the unit.                     The following table shows the relationship between the number of the grid unit of the birth and the P value.              The calculations for the children of SeM and his mate are shown below.  The E value is the number of SeM’s mate, namely 360.  SeM and his mate didn’t need a table like the one above.  They knew that P was 0 on their land just as we know the zip code nmumber of our community.  We, a few thousand years later, are just learning the system, so we need a table like the one above to determine the P value.                 The E value in SeM’s family is E=360.  In the table above,  360 falls in the range of 343 through 361, and the corresponding P value is 665 or 0.  For that reason, the  P value in aRPaHSaD’s name is P=0.        For those who don’t like to work with tables, there are equations for calculating the P and K values, and for those who don’t like to use equations, the long division method is demonstrated at the bottom of this lesson.  But for now, let’s calculate with the below blue equations..     P=19(INT(E/19)+1)+304        In aRPaHSaD’s case, the E=360, so   P=19(INT(360/19)+1)+304   =19(INT(18.95)+1)+304   =19(18+1)+304 or (19 times 19)+304   =361+304=665 P=0   K=35(20-19(E/19-INT(E/19))     K=35(20-19(E/19-INT(E/19)), E=JoKTaN=653    =35(20-19(360/19-INT(360/19))    =35(20-19(18.95-18))    =35(20-19(.95))=35(20-18)=35*2=70        The blue equation for the K value doesn’t match what the people born where aRPaHSaD was born actually used.  The actual K value is 105.  What that says is that the unit directly West of SeM’s unit number 342, and directly North of SeM’s mate’s unit, number 360, is the place where SeM and his mate spent some of their time.  SeM’s mate’s unit is the second unit North of the boundary.  The children were born one unit further North where the K=3 times 35=105.                   PELeG is the next person in the SeM line with a P value in the name.  Although Genesis 11:16 states that EBeR begat PELeG, Genesis 10:21 states that SeM is the father of the children of EBeR.  It turns out that the meaning of this statement is that PELeG and his brother JoKTaN were born on SeM’s land, the same land on which aRPaHSaD was born, namely, where P=0 and K=105.  The K=105 statement is explained above.                            PELeG=P+E+30+3=33+P+E, E=SeM=340                             =0+340+30+3=373        PELeG’s actual father, EBeR, was also number 373.  EBeR’s father was SALá.                           SALá=300+A+30+1=331+A, A=aRPaHSaD=505                            =331+505=836-665=171                           EBeR=E+2+200=202+E, E=SALá=171                            =171+2+200=373       Don’t forget the aRPaHSaD code from Lesson 1.  In that code the E value represents a parent’s number, and the A=505 represents aRPaHSaD’s number.             There is no table to calculate a K value, so we must use one of the following equations.  West of the Euphrates, the equation that SeM’s family used to calculate the K value is—                                                          K=35(20-19(E/19-INT(E/19)),         East of the Euphrates, the equation changes, and becomes-                      K=35(19(E/19-INT(E/19)).        SERuK was PELeG’s grandson.  SERuK’s father was REU, the man whose number is 666, so the half-equation of SERuK’s name is—                           SERuK=300+E+200+K=500+E+K, E=REU=1                             =500+E+K        Since SERuK was born on REU’s property- namely UR of the Chaldees- which is considered to be east of the Euphrates, the second equation above should be used to calculate the K value in SERuK’s name.                           K=35(19(1/19-INT(1/19)), where E=REU=1.                        35(.053-0)=35(1)=35                                                         So,   SERuK=500+1+35=536        JoKTaN’s used the P and K sounds in the names of some of his children.  The results of the calculations of the numbers of his family are shown below.  The E=653, and according to the table, the P=304.  Let’s test the blue equations shown above and see if they give calculations that match the calculations derived using the named-equations.          P=19(INT(E/19)+1)+304, E=JoKTaN=653   =19(INT(653/19)+1)+304                        =19(34+1)+304=35(19)+304   =665+304=0+304=304   The P value checks-out.  How about the K value.   K=35(20-19(E/19-INT(E/19)), E=JoKTaN=653   =35(20-19(653/19-INT(635/19))   =35(20-19(34.368-34))   =35(20-19(.368))=35(20-7)=13*7=455        The K value also checks-out.  What do you know?  The equations worked again.  The E value represents JoKTaN’s number.  Later, the fact that the J value in JoKTaN’s name is 98, the number of years he was born after the flood, will be explained.  For now have faith that the J=98 in JoKTaN’s name.  Since he was born in the same place as aRPaHSaD and his brother, PELeG, the K=105 in his name.         JoKTaN=98+105+400+50=653, J=98 years after the flood, K=105 on SeM’s land.  So, the E=653 calculation is correct, and another test, using the table and the equations, passes.         Lets try the equations on the children of NaHOR and Mílká.  These kids were born on MíLKá’s property, which is number 426.  If MíLKá’s had used an E in any of her children’s names, it’s value would have been 426.                   According to the table, if E=426 then P=76.  The table gives the correct P value for this family.  Let’s try the blue equations again.   P=19(INT(E/19)+1)+304, E=MíLKá=426 =19(INT(426/19)+1)+304 =19(INT(22.421)+1)+304 =19(22+1)+304)=19*23+304 =437+304=741-665=76   K=35(20-19(E/19-INT(E/19)), E= MíLKá=426 =35(20-19(22.421-22))=35(20-8) =35*12=420                            The table and the equations worked again. The SeM family members that descended from ABRaM and were born in BEERSEBá, changed the code.  They used the P=0 and K=420 values.  The children of JaKoB were born on LABaN’s land, unit number 310.  First, let’s calculate JaKoB’s number, and then see if the table and the equations work with the people born on LABaN’s land.         JaKoB had another name.  It was íSRAáL.  He also had a twin brother whose name was ESAA.  The numbers of these three names should be identical, because the names belong to people born on the same day.     ESAA=300+E+2A.  E=IZAAK=154, A=ABRaM=82, so          300+154+82+82=618.   JAKoB=2+J+A+K.  J=2109AA, A=ABRaM=82, K=420 in BEERSEBá, so                2+2109+82+420=2613-1995=618.   ÍSRAáL=536+A.  A=ABRaM=82, so                      536+82=618.                       IZAAK was born in BEERSEBá, where K=420.  The I value represents a very popular ancestor whose number is 228.  It is the E value in TERá’s name, and the A value in LABaN’s name.  TERá is ABRaM’s father.  The person whose number is 228 is probably the mate of TERá’s father, NAHOR, whose number is 267.    TERá=601+E=601+228=829-665=164   IZAAK=7+I+2A+K.  I=probably a parent of TERá=228, A=ABRaM=82, the K in             BEERSEBá=420.        =7+228+82+82+420=819-665=154                        JAKoB moved to LABaN’s property where he acquired two wives and two concubines.  All four women delivered children by him.               This family used the O value to tell on whose land the family was using, and where they delivered their children.  Let’s test the table and the blue equations again.   According to the table, if the number is 310, LABaN’s number, the P value is 627.  The table is correct again.  How about the blue equations.  Now the E term in the equation is replaced with the O value.   P=19(INT(O/19)+1)+304, O=LABaN=310        =19(INT(310/19)+1)+304 =19*(INT(16.316)+1)+304=19*(16+1)+304=323+304=627   K=35(20-19(O/19-INT(O/19)), O=LABaN=310   =35(20-19(16.316-16)) =35(20-19*.316)=35(20-6)=490                        And the equations work again.  What are the odds of this system not being an actual part of history?        Calculating the P and K values – Long division works too.        Some people have forgotten some of the algebra they learned, and some have never taken an algebra class, so the term ”INT(E/19)” used in the equations introduced in lesson 2A isn’t too familiar.  For this reason, an additional        method of doing the arithmetic needed to calculate the P and K values follows.         Training in ”long division” began in grammar school.  The following demonstration uses number 360, the number of SeM’s mate, to describe the steps needed for calculating a P and a K value using long division. Calculate the P value. Step one – Divide the unit number by 19.  (360/19=18 with a remainder of 8. Step two – Drop the remainder from the results of step one.  This leaves 18. Step three – Add 1 to the results of step two.  (18+1=19). Step four – Multiply the results of step three by 19.  (19 times 19 = 361) Step five – Add 304 to the results of step four to get the P value.  (304 + 361 = 665 = 0).        Calculating with long division gives the same result for the P value as the table gave, and the blue equation gave, namely P=0 in the names of SeM’s children.  Now for the K calculation.        Calculate the K Value. Step one – Subtract the remainder from 20.  (20-18 = 2). Step two – Multiply the results of step two by 35.  (2 times 35 = 70).        And again, long division give the same value that the blue equation gave, namely K=70.  But don’t forget, the K value in the names of the children of SeM is 105, three rows up from the grid boundary.  The diagram below should explain this apparent flaw in the K value calculatiion. SeM and the mate decided to use the land that was adjacent to both of them to good advantage.  SeM’s mate travelled north, and SeM travelled west where they joined forces to make their home.          JAKoB’s grandchildren were born in BEERSEBá where they used the P=0 and K=420 values in their names.  The SeM P and K code picks up again after DAViD’s and SoLoMoN’s time.  The calculations of these names will be shown in a later lesson.    ◊◊◊       4:53:33 PM    comment []